How do you solve $3( x - 2) ^ { 2} + 5= 26$ ?

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Answer 1 · 2017-11-14T03:31:12

Isolate $x$ by doing the opposite of BEDMAS to the total.

Solving implies determining the value of the variable.

In order to solve this equation, we do the opposite of BEDMAS and isolate $x$ .

$3(x-2)^2+5=26$

First off, let's "remove" the $5$ , by subtracting it from the total.

$3(x-2)^2=21$

Now, we divide everything by $3$ to remove the $3$ .

$(x-2)^2=7$

Now, we have square root the $7$ to remove the squared step.

$x-2=sqrt7$

Finally. we add $2$ to the total in order to fully isolate $x$ .

$x=sqrt7+2$

We can double check this by subbing in $x=sqrt7+2$ and compare the answers.

$3(x-2)^2+5=26$

$3[(sqrt7+2)-2]^2+5=26$

$3[(sqrt7)]^2+5=26$

$3(7)+5=26$

$21+5=26$

$26=26$

Hope this helps :)

How do you solve 3( x - 2) ^ { 2} + 5= 263( x - 2) ^ { 2} + 5= 26?