Question #76b2d

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Question #76b2d

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Answer 1 · 2017-11-14T14:08:58

distance : $π \cdot \frac{r}{2}$ $pi*r/2$
displacement: $\sqrt{2} r$ $sqrt2r$

Explanation:

Let us consider a coordinate axis with the center as the center of the circular .

As the radius of the circle is r . initially consider the body is situated in the x axis at a distance r from the center .

we are given that the body has traveled 1/4th of the of the circle

the distance traveled by it will be $\frac{2 \cdot π \cdot r}{4}$ $(2*pi*r)/4$ (because 2 $π r$ $pir$ will be distance traveled by the body when it completes the whole circle

DISPLACEMENT:

When it travels 1/4th of the distance at final it will be at the y axis at a distance r from the center

applying pythagoras theorem the displacement will be $\sqrt{r^{2} + r^{2}} \Rightarrow \sqrt{2 r^{2}} \Rightarrow \sqrt{2} r$ $sqrt(r^2+r^2)=>sqrt(2r^2)=>sqrt2r$

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Question #76b2d

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