How do you solve for $x$ in $\frac { 9} { w + 8} = \frac { x } { ( w - 7) ( w + 8) }$ ?

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Answer 1 · 2017-11-15T06:05:15

$=>x = 9w -63$

$\frac { 9} { w + 8} = \frac { x } { ( w - 7) ( w + 8) }$

By transposition:

$=> 9 = \frac { x( w + 8) } { ( w - 7) ( w + 8) }$

$=> 9 = \frac { xcancel( (w + 8)) } { ( w - 7) cancel( w + 8) }$

$=> 9 = \frac { x} { ( w - 7) }$

$=>9(w-7) = x$

$=>9w -63 =x$

$=> x = 9w-63$

Answer 2 · 2017-11-15T06:10:34

$x=9(w-7)$

Start by cancelling $w+8$ from both sides of the equation

$9/(cancel(w+8))=x/((w-7)cancel((w+8)))$

$9=x/(w-7)$

Multiply both sides by $w-7$ , cancelling it on the right.

$9color(red)((w-7))=x/cancel(w-7)cancel(color(red)((w-7)))$

$9(w-7)=x$

Rewriting from left to right,

$x=9(w-7)$

How do you solve for xx in \frac { 9} { w + 8} = \frac { x } { ( w - 7) ( w + 8) } \frac { 9} { w + 8} = \frac { x } { ( w - 7) ( w + 8) }?