Question #627ac

1 Answer
Nov 15, 2017

m=-1/2m=12

Explanation:

we take

x^3y^3=8x3y3=8

taking out cube root

xy=2xy=2

isolate the variable y

y=2/xy=2x

deriving to find the slope of the line tangent to the curve

y'=-2/x^2

on the point (2,1) -> x=2

substitute in the derivative

y'=-2/(2^2)

y'=-1/2

the tangent line will be given by the point-slope equation

y-y_o=m(x-x_o)

y-1=-1/2(x-2)

operating

x+2y-4=0