Question

How do you solve `\frac { 18} { x - 2} - \frac { 4} { x - 1} = \frac { 4} { x ^ { 2} - 3x + 2}`?

Answer 1

It has no solution.

Explanation:

First of all we do the gcf between `(x-2)` and `(x-1)`, that's found by multiplying them with each other,
`(x-2)(x-1)=x^2-3x+2`

so now we have this:
`(18-4)/(x^2-3x+2)=4/(x^2-3x+2)`

we can simplify the divisors:
`(18-4)/cancel(x^2-3x+2)=4/cancel(x^2-3x+2)`

`18-4=4`

As you can see, there's no x in the equation, what means that there's no solution to this equation.