How do you solve $8 (2 + 3 n) = 32 + 8 n$ $8( 2+ 3n ) = 32+ 8n$ ?

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How do you solve $8 (2 + 3 n) = 32 + 8 n$ $8( 2+ 3n ) = 32+ 8n$ ?

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Answer 1 · 2017-11-19T01:27:17

$n = \frac{1}{2}$ $n=1/2$

Explanation:

Law:
$a \cdot (b + c) = a \cdot b + a \cdot c$ $a*(b+c)=a*b+a*c$

$8 \cdot (2 + 3 n) = 32 + 8 n$ $8*(2+3n)=32+8n$

using the law:
$a \cdot (b + c) = a \cdot b + a \cdot c$ $a*(b+c)=a*b+a*c$
when:
$a = 8$ $a=8$
$b = 2$ $b=2$
$c = 3 n$ $c=3n$

$\Rightarrow 8 \cdot 2 + 8 \cdot 3 n = 32 + 8 n$ $=> 8*2+8*3n=32+8n$
$\Rightarrow 16 + 24 n = 32 + 8 n$ $=> 16+24n=32+8n$

minus $8 n$ $8n$ minus $16$ $16$

$\Rightarrow 16 + 24 n - 8 n - 16 = 32 + 8 n - 8 n - 16$ $=> 16+24n-8n-16=32+8n-8n-16$
$\Rightarrow (16 - 16) + (24 n - 8 n) = (32 - 16) + (8 n - 8 n)$ $=> (16-16)+(24n-8n)=(32-16)+(8n-8n)$
$\Rightarrow (0) + (32 n) = (16) + (0)$ $=> (0)+(32n)=(16)+(0)$
$\Rightarrow 32 n = 16$ $=> 32n=16$

divided by $32$ $32$

$\Rightarrow \frac{32 n}{32} = \frac{16}{32}$ $=> (32n)/32=16/32$
$\Rightarrow (\frac{32}{32}) n = (\frac{16}{32})$ $=> (32/32)n=(16/32)$
$\Rightarrow (1) n = (\frac{1}{2})$ $=> (1)n=(1/2)$
$\Rightarrow n = \frac{1}{2}$ $=> n=1/2$

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How do you solve $8 (2 + 3 n) = 32 + 8 n$ $8( 2+ 3n ) = 32+ 8n$ ?

1 Answer

Explanation:

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