If y = cosx^3sin^2(x^5)y=cosx3sin2(x5), what is dy/dxdydx?

1 Answer
Nov 19, 2017

See explanation

Explanation:

According to the product rule,
d/dx[f(x)*g(x)]=f(x)*g'(x)+g(x)*f'(x), where f(x) = cos(x^3) and g(x) = sin^2 (x^5)

Therefore (be careful with the chain rule),
d/dx [cosx^3 *sin^2 (x^5)] = cosx^3 * 2sin(x^5) * cos(x^5) * 5x^4 +sin^2(x^5) * -sin(x^3)*3x^2

That can be re-written or simplified as:
x^2sin(x^5)(10x^2cos(x^3)cos(x^5)-3sin(x^3)sin(x^5))