Question #2c02b

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Question #2c02b

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Answer 1 · 2017-11-19T01:49:09

$x_{1} = 1 \frac{2}{3} \approx 1.667$ $x_1=1 2/3~~1.667$
$x_{2} = \frac{1}{5} = 0.2$ $x_2=1/5=0.2$

Explanation:

$a x^{2} + b x + c = 0$ $ax^2+bx+c=0$
$x_{1, 2} = \frac{- b \pm \sqrt{b^{2} - 4 \cdot a \cdot c}}{2 \cdot a}$ $x_(1,2)=(-b+-sqrt(b^2-4*a*c))/(2*a)$

$15 x^{2} - 28 x + 5 = 0$ $15x^2-28x+5=0$
$\Rightarrow$ $=>$
$a = 15$ $a=15$
$b = - 28$ $b=-28$
$c = 5$ $c=5$
$\Rightarrow$ $=>$
$x_{1, 2} = \frac{- (- 28) \pm \sqrt{{(- 28)}^{2} - 4 \cdot (15) \cdot (5)}}{2 \cdot (15)} =$ $x_(1,2)=(-(-28)+-sqrt((-28)^2-4*(15)*(5)))/(2*(15))=$
$= \frac{28 \pm \sqrt{784 - 300}}{30} =$ $=(28+-sqrt(784-300))/(30)=$
$= \frac{28 \pm \sqrt{484}}{30} =$ $=(28+-sqrt(484))/(30)=$
$= \frac{28 \pm 22}{30} =$ $=(28+-22)/(30)=$
$\Rightarrow$ $=>$
$x_{1} = \frac{28 + 22}{30} = \frac{50}{30} = \frac{5}{3} = 1 \frac{2}{3} \approx 1.667$ $x_1=(28+22)/(30)=50/30=5/3=1 2/3~~1.667$
$x_{2} = \frac{28 - 22}{30} = \frac{6}{30} = \frac{2}{10} = \frac{1}{5} = 0.2$ $x_2=(28-22)/(30)=6/30=2/10=1/5=0.2$

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Question #2c02b

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