How do you solve x3x211x+11=0?

1 Answer
Nov 19, 2017

x1=1
x2=11
x3=11

Explanation:

x3x211x+11=0
x2(x1)11(x1)=0

let x1=t
x2(t)11(t)=0
(x211)(t)=0

(x211)(x1)=0

So:
(x1)=0x=1
OR
(x211)=0x=±11