A rectangle has sides $x^2 + 4x$ and $4x+12$ , what is its area?

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Answer 1 · 2017-11-20T06:46:17

The area of the rectangle is $4x^3+28x^2+48x$ units squared.

A rectangle's area is calculated by using the formula: $A=lw$ . Other variants include $A=bh$ .

$A=lw$

$=(x^2+4x)(4x+12)$

At this point, we are now going to foil the equation. This is how you multiply two binomials.

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$=4x^3+12x^2+16x^2+48x$

Now we simplify.

$=4x^3+28x^2+48x$

Therefore, the area of the rectangle is $4x^3+28x^2+48x$ units squared.

Hope this helps :)

A rectangle has sides x^2 + 4xx^2 + 4x and 4x+124x+12, what is its area?