Question

Question #77aa9

Answer 1

See Below.

Explanation:

We will use the equation `q=s*m*DeltaT` where `q` is heat, `s` is the specific heat, `m` is the mass, and `DeltaT` is the change in temperature. So far, we can plug in these numbers:

`1,921=s*22.32*110.2`, which we can simplify to:

`1,921=s*2,459`

Now, we can solve for `s` algebraically by dividing by 2,459 on both sides:

`0.7812=s`

The units of specific heat capacity are in `"J"/("gram"*C)`

I hope this helps!