Question

How do you solve `3( x - 1) - 2x - 3+ 15= \frac { 4x - 1} { 3} + x + \frac { 1} { 12}`?

Answer 1

`x=111/16`

Explanation:

`3(x-1)-2x-3+15={4x-1}/3+x+1/12`

`3x-3-2x-3+15={4x-1}/3+x+1/12`

`x+9={4x-1}/3+x+1/12`

`9={4x-1}/3+1/12`

`108=16x-4+1`

`16x=111`

`x=111/16`

Answer 2

The answer is `x = 111/16`

Explanation:

We have the question

`3(x-1) - 2x -3 + 15 = "4x-1"/3 + x + 1/12`

Removing the parentheses,

We get,

`3x-3 - 2x -3 + 15 = "4x-1"/3 + x + 1/12`

From addition and subtraction of 'similar' terms. We get,

`x+9 = "7x-1"/3 +1/12`

Now separating keeping similar terms in one side. We have,

`9 - 1/12 = "7x-1"/3 - x`

(Note: The change in sign occurs due to the shifting of term from one side to the other)

Now by simplifying,

`107/12 = "4x-1"/3`

Multiplying both sides by 12. We get,

`107/12 * 12 = "4x-1"/3 * 12`

or `107 = 16x -4`

Adding 4 to both sides. We get,

or `107 +4 = 16x -4 +4`

or `111 = 16x`

Now dividing both sides by 16. We get,

or `111/16 = "16x"/16`

Thus, Giving

`x = 111/16`