Question #9cca0

1 Answer
Nov 22, 2017

22.4L

Explanation:

At standard temperature and pressure (0 Celsius and 1.00 atm) 1 mol of an ideal gas will occupy 22.4L.

This can be seen in this equation by solving for V:

PV=nRT where P is pressure in atm, V is volume in L, n is the number of moles, R is the gas constant 0.08206 Latm, and T is the temperature in Kelvin. Let's plug in STP for 1 mol of gas:

1.00V=(1.00R273)

1.00V=22.4

Thus, V=22.4