Question

Question #ab6d1

Answer 1

See below.

Explanation:

We already have a balanced chemical equation, so now the only thing we have to do is the stoichiometry:

Step 1: Convert grams of `LiOH` into moles using its molar mass.

`"10.0 g LiOH"*((1 mol LiOH)/(23.948 grams))="0.418 mols LiOH"`

Step 2: Use the mol ratio of `LiOH` to `LiBr` to find how many mols of `LiBr` will be produced.

`"0.418 mols LiOH"*((1 mol LiBr)/(1 mol LiOH))="0.418 mols LiBr"`

Step 3: Convert mols of `LiBr` to grams using its molar mass.

`"0.418 mols LiBr"*((86.845g)/(1 mol LiBr))="36.3 grams LiBr"`

Hope this helps!