How do you solve the right triangle ABC given a=2, B=8?

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Answer 1 · 2017-11-23T15:28:19

Below

Given
#B=8^o#
and a right triangle
#C=90^o#

Angle A could be determined by
# (180-90-8)#= #82^o#

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Hence we could solve for b
#tan(82)=2/b#

#btan(82)=2#

#b=2/tan(82)#

#b=14.23#

Using pythagorean theorem

#c=sqrt(a^2+b^2)#

#c=sqrt(2^2+14.23^2)#

c=14.37

Therefore

A=82
B=8
C=90

a=2
b=14.23
c=14.37