How do you multiply and simplify $(- 2 x^{2} y^{3} z) {(- 3 x^{2} y^{3} z^{3})}^{4}$ $(- 2x ^ { 2} y ^ { 3} z ) ( - 3x ^ { 2} y ^ { 3} z ^ { 3} ) ^ { 4}$ ?

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Answer 1 · 2017-11-25T07:52:58

$- 162 x^{10} y^{15} z^{13}$ $-162x^10y^15z^13$

Given:
$(- 2 x^{2} y^{3} z) \cdot {(- 3 x^{2} y^{3} z^{3})}^{4}$ $(-2x^2y^3z)*(-3x^2y^3z^3)^4$

We square the second part of the equation twice to arrive at the result below:

$(- 2 x^{2} y^{3} z) \cdot (81 x^{8} y^{12} z^{12})$ $(-2x^2y^3z)*(81x^8y^12z^12)$

From here, group the like terms together and multiply them as so;

$- 162 x^{10} y^{15} z^{13}$ $-162x^10y^15z^13$ .

How do you multiply and simplify (−2x2y3z)(−3x2y3z3)4(- 2x ^ { 2} y ^ { 3} z ) ( - 3x ^ { 2} y ^ { 3} z ^ { 3} ) ^ { 4}?