Question

How do you solve `1.1x + 1.2x - 5.4= - 10`?

Answer 1

`x=-2`

Explanation:

`1.1x+1.2x-5.4=-10`

`2.3x-5.4=-10` (combine like terms)

`2.3xcancel(-5.4+5.4)=-10+5.4` (add `5.4` on both sides)

`2.3x=-4.6`

`(cancel(2.3)x)/cancel(2.3)=-4.6/2.3` (divide by `2.3` on both sides)

`x=-2`

Answer 2

`x=-2`

Explanation:

`"simplify left side"`

`rArr2.3x-5.4=-10`

`"isolate the term in x by adding 5.4 to both sides"`

`2.3xcancel(-5.4)cancel(+5.4)=-10+5.4`

`rArr2.3x=-4.6`

`"divide both sides by 2.3"`

`(cancel(2.3) x)/cancel(2.3)=(-4.6)/2.3`

`rArrx=-2" is the solution"`

Answer 3

Just use this simple easy steps below;

Explanation:

We have;

`1.1x + 1.2x - 5.4 = - 10`

First simplify by adding the `x` variables..

`2.3x - 5.4 = - 10`

Now, we Add both sides by `5.4` to let `x` be on its own..

`2.3x - 5.4 + 5.4 = - 10 + 5.4`

`2.3x + 0 = - 10 + 5.4`

`2.3x = - 10 + 5.4`

`2.3x = -4.6`

We what `x` to stand on its own, to achieve that, we divide both sides by its constant `2.3`

`(2.3x)/2.3 = - 4.6/2.3`

`(cancel2.3 x)/cancel2.3 = - 4.6/2.3`

`x = - 4.6/2.3`

`x = - 2`

Hope this helps!