How do you evaluate $(8x - 4x ^ { 2} + 8) + ( 5+ 5x ^ { 2} + 5x ) - ( 8+ 7x - 6x ^ { 2} )$ ?

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Answer 1 · 2017-11-28T05:18:47

As it is just addition collect the coefficients

$f(x) = (8x-4x^2+8)+(5+5x^2+5x)-(8+7x-6x^2)$
$= x^2(-4+5-(-6))+x(8+5-7)+(8+5-8)$
$=7x^2+6x+5$

How do you evaluate (8x - 4x ^ { 2} + 8) + ( 5+ 5x ^ { 2} + 5x ) - ( 8+ 7x - 6x ^ { 2} )(8x - 4x ^ { 2} + 8) + ( 5+ 5x ^ { 2} + 5x ) - ( 8+ 7x - 6x ^ { 2} )?