Question

Question #6ccef

Answer 1

This graph will have a y value equal to -5 times your x value. It will look like a very steep downward slope.

Explanation:

Here's how we know:

The equation for any linear equation can be put into

`y =`m`x +`b format.

m, is the slope. It shows how steep the line will be (up or down).

In this case, your slope is -5, which means each time we plug in a value for x (on the horizontal axis), y will be -5 times that. So we can just imagine here...

x vs. y

0 0

1 -5

2 -10

-1 5

And here's the graph!

graph{y = -5x [-10, 10, -5, 5]}

By the way, if you are wondering what the b is for your graph, it's 0! This is because you didn't put anything down for it, so automatically y intercepts the graph at 0. This makes sense because when x is 0, y is 0 and there is no buffer (nothing added to x to make it more than 0)

Answer 2

The graph for `y = -5x`.
graph{-5x [-10, 10, -5, 5]}

Explanation:

The way to draw a graph is to understand how to plot points. A point is something which is on a graph and looks like `(x, y)`. If you choose an x-value, then find out the y-value, and then plot it on the graph. For example, with `y = -5x`, I will do a plot table for you:

• When x = 0, y = 0.
• When x = 1, y = -5.
• When x = 2, y = -10.
• When x = -1, y = 5.
• When x = -2, y = 10.

So in the end, you have a bunch of points which should look like this:

• `(-5, 25)`
• `(-4, 20)`
• `(-3, 15)`
• `(-2, 10)`
• `(-1, 5)`
• `(0, 0)`
• `(1, -5)`
• `(2, -10)`
• `(3, -15)`
• `(4, -20)`
• `(5, -25)`

Now, you have a bunch of points. You are ready to plot them on a graph. Just draw a graph, label the x and y axis, and then start plotting.

To plot a point such as `(x, y)`, you have to move right or left (if negative) across the x-axis `x` distance and move up or down (if negative) the y-axis.

Now that you have plotted all the points, you should have a bunch of dots. Simply connect the dots. You should get a line which looks similar to the line above.

Now, you can't plot an infinite amount of points but you have think whether the graph continues the way it started, in a straight line. In this case, it does.

Now, you should have the graph. I hope this helped and I hope I answered what you were asking for.