How do you evaluate $\frac{20 (15 - 4) - 4 (8 - 4)}{10 (2 - 6) - 2 (4 + 2)}$ $\frac { 20( 15- 4) - 4( 8- 4) } { 10( 2- 6) - 2( 4+ 2)$ ?

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Answer 1 · 2017-11-30T23:48:51

$204/-52 or -3.92307...$

Follow BEDMAS (bracket, exponent, division, multiplication, addition, subtraction.)

Let’s solve the brackets first, so

$((20(15-4)-4(8-4)))/((10(2-6)-2(4+2)))$

$=((20(11)-4(4)))/((10(-4)-2(6)))$

Now lets multiply where needed.

$= (((220)-(16)))/(((-40)-(12)))$

Then subtraction/addition

$= ((204))/((-52))=-3.9230769231$

How do you evaluate \frac { 20( 15- 4) - 4( 8- 4) } { 10( 2- 6) - 2( 4+ 2) 20(15−4)−4(8−4)10(2−6)−2(4+2)\frac { 20( 15- 4) - 4( 8- 4) } { 10( 2- 6) - 2( 4+ 2) ?