How do you evaluate #7^ { 2} - 4^ { 2} \times 3#?

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Answer 1 · 2017-12-03T02:25:29

1

Follow BEDMAS (Bracket, exponent, division, multiplication, addition, subtraction)

Let's solve the exponents first, so:

#7^2-4^2*3#

#= 49 - 16 *3 #

Following BEDMAS, we multiply next

#49-16*3#

#=49-48#

And then we subtract

#49-48=1#