How do you multiply #(9x ^ { 3} - 8) ( x ^ { 9} - 3)#?

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Answer 1 · 2017-12-03T02:36:56

#=9x^12-8x^9-27x^3+24#

Follow the FOIL rule (First, Outer, Inner, Last)
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#(9x^3-8)(x^9-3)#

Note: When dealing with exponents, follow the exponent laws. image.mathcaptain.com

#(9x^3*x^9)+(9x^3*-3)+(-8*x^9)+(-8*-3)#

Note: (negative) #*# (negative) = (positive)

#(9x^(3+9))+(-27x^3)+(-8x^9)+(24)#

#9x^12-27x^3-8x^9+24#

I'm just going to rearrange it in descending order of x

#=9x^12-8x^9-27x^3+24#