How do you simplify #\frac { - 2- ( 6) } { 6- 8} #?

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Answer 1 · 2017-12-03T20:27:26

I will show you the steps:

1)#(-2-6)/(6-8)#

First, simplify the subtractions

#-2-6=-8#

and #6-8=-2#

2) now you have: #(-8)/(-2)#

3) Then, simplify #(-8)/-2:" " (-8div2)/(-2div2)= (-4)/-1=4#

4) The answer is: #(-4)/(-1) = 4/1 = 4#