Question #05079

1 Answer
Steelballs
Dec 4, 2017

KE of mass 2= 1.2*10^-81.2⋅10−8 J

Explanation:

Using conservation of momentum:
m1v1=m2v2

m1= 1.6 * 10^-251.6⋅10−25 kg
m2= 2.4 * 10^-252.4⋅10−25 kg

KE of m1=18*10^-918⋅10−9 J =0.5m1v1^20.5m1v12
We can find v1=4.74*10^84.74⋅108 m/s

m1v1=m2v2
v2=(m1v1)/(m2)m1v1m2
v2=3.16*10^83.16⋅108 m/s

KE of m2=0.5m2v2^20.5m2v22=0.5*(2.4*10^-25)*((3.16*10^8)^2)0.5⋅(2.4⋅10−25)⋅((3.16⋅108)2)=1.2*10^-81.2⋅10−8 J

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