2x^2=-4x-1 using quadratic formula?

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Answer 1 · 2017-12-04T19:09:50

$\frac{1}{2} (- 2 \pm \sqrt{2})$ $1/2(-2+-sqrt(2))$

Rearrange the equation

$2 x^{2} + 4 x + 1 = 0$ $2x^2+4x+1=0$

The equation above is a form of the general quadratic equation

$a x^{2} + b x + c$ $ax^2+bx+c$

Substitute values in the quadratic formula
On the calculator it will give the answer:

$\frac{1}{2} (- 2 \pm \sqrt{2})$ $1/2(-2+-sqrt(2))$