How do you write the vertex form equation of the parabola #y=x^2 - 8x + 3#?

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Answer 1 · 2017-12-04T21:30:56

#y+13=(x-4)^2#

have

#(x-h)^2=4p(y-k)#

#y=x^2-8x+3#

completing squares

#y=x^2-8x+16-16+3#

#y=(x-4)^2-13#

#y+13=(x-4)^2#

then vertex is (h,k)

#V(4,-13)#