How do you write the vertex form equation of the parabola $y = x^{2} - 8 x + 3$ $y=x^2 - 8x + 3$ ?

Question

1651 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-04T21:30:56

$y + 13 = {(x - 4)}^{2}$ $y+13=(x-4)^2$

have

${(x - h)}^{2} = 4 p (y - k)$ $(x-h)^2=4p(y-k)$

$y = x^{2} - 8 x + 3$ $y=x^2-8x+3$

completing squares

$y = x^{2} - 8 x + 16 - 16 + 3$ $y=x^2-8x+16-16+3$

$y = {(x - 4)}^{2} - 13$ $y=(x-4)^2-13$

$y + 13 = {(x - 4)}^{2}$ $y+13=(x-4)^2$

then vertex is (h,k)

$V (4, - 13)$ $V(4,-13)$

How do you write the vertex form equation of the parabola y=x2−8x+3y=x^2 - 8x + 3?