Question

Question #875ac

Answer 1

Using various properties of a mol, the volume of one `"Hg"` atom is `"2.44895 * 10^-23` `"cm"^3`.

Explanation:

First, let's determine the overall volume of one mole of `"Hg"`. The molar mass of `"Hg"` is `"200.6 g/mol"`, so there are `"200.6 g"` of `"Hg"` in one mole of `"Hg"`.

We know the number of atoms in one mole, so we'll use `"200.6 g"` as mass. The formula for density is :

`d=m/V`

Switching between the variables will leave us with this:

`V=m/d`

Substitute the values:

`"200.6 g"/"13.6 g/cm"^3 = V`

And you get the volume of one mole as `"14.75 cm"^3`. The number of atoms in one mol is `6.022 * 10^23` atoms. Divide the volume by the number of atoms to get `2.44895 * 10^-23` `"cm"^3`.