How do you divide $\frac{\sqrt{- 48}}{\sqrt{4 \sqrt{- 3}}}$ $\frac { \sqrt { - 48} } { \sqrt { 4\sqrt { - 3} } }$ ?

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Answer 1 · 2017-12-06T03:52:40

Concepts of complex numbers are being used here.

The expression can be rewritten as

$= \frac{48 i}{2 \cdot \sqrt[4]{3} \sqrt{i}}$ $=(48i)/(2*root4 3sqrti)$

$= \frac{24 i}{\sqrt[4]{3} \sqrt{i}}$ $=(24i)/(root4 3sqrti)$

$= \frac{3^{\frac{3}{4}} \cdot 8 i}{\sqrt{i}}$ $=(3^(3/4)*8i)/(sqrti)$

How do you divide \frac { \sqrt { - 48} } { \sqrt { 4\sqrt { - 3} } }√−48√4√−3\frac { \sqrt { - 48} } { \sqrt { 4\sqrt { - 3} } }?