How do you solve $\log _ { 2} ( 9- 4x ) = 3$ ?

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Answer 1 · 2017-12-07T02:22:11

$x=1/4=0.25$ .
See explanation.

You have:
$log_2 (9-4x) =3$

so you can do:
$2^[log_2 (9-4x)] =2^3$

which becomes:
$(9-4x) = 2^3$

and just solve for x:
$4x = 9-8$
i.e.
$x=1/4=0.25$

How do you solve \log _ { 2} ( 9- 4x ) = 3\log _ { 2} ( 9- 4x ) = 3?