Question #d9b17

1 Answer
TreeReader
Dec 10, 2017

#x<-4," and " x> -1#

Explanation:

Plotting the graph:
As #x^2+5x+4=0# factorises as #(x+4)(x+1)# the #x# intercepts are at #y= -1" and" -4#.
Y-intercept is at #x= 4#
Coefficient is 1 so normal out 1 up 1 parabola)
Hence:
graph{x^2+5x+4 [-7, 3, -5, 10]}

Now your question is for an inequality not an equation, so the answer is the area of the graph which is bigger than zero.

So this is everywhere above the #x#-axis:
graph{(x^2+5x+4)>0 [-7, 3, -5, 10]}

#:. x<-4, x> -1#

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