How do you solve #9y-43=3y+71#?

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1 Answer
Ayse K. · Kushagra
Dec 12, 2017

You basically combine like terms and divide in order to solve this equation

Explanation:

#9y-43=3y+71#
subtract 3y from both sides
#6y-43=71#
Now add 43 on both sides
#6y=114#
divide both sides by 6
#(cancel6y)/cancel6 = cancel114^19/cancel6^1#
#y=19#

Your answer is 19

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