If $p (x) = x^{2} - 1$ $p(x) = x^2 -1$ and $q (x) = 5 (x - 1)$ $q(x) = 5(x-1)$ , what is $(p - q) (x)$ $(p-q)(x)$ ?

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If $p (x) = x^{2} - 1$ $p(x) = x^2 -1$ and $q (x) = 5 (x - 1)$ $q(x) = 5(x-1)$ , what is $(p - q) (x)$ $(p-q)(x)$ ?

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Answer 1 · 2017-12-13T00:30:06

$x^{2} - 5 x + 4$ $x^2-5x+4$

Explanation:

$(p - q) (x) = p (x) - q (x) = (x^{2} - 1) - 5 \cdot (x - 1) = x^{2} - 5 x + 4$ $(p-q) (x)=p(x)-q(x)=(x^2-1)-5*(x-1)=x^2-5x+4$

Answer 2 · 2017-12-13T00:34:30

$x^{2} - 5 x + 4$ $x^2- 5x+4$

Explanation:

Question, $(p - q) (x)$ $(p-q)(x)$

Here both $p$ $p$ and $q$ $q$ are functions assuming $(p - q) (x)$ $(p-q)(x)$ means $p (x) - q (x)$ $p(x)-q(x)$ .

$(p - q) (x) =$ $(p-q)(x) =$
$p (x) - q (x)$ $p(x)-q(x)$

$= p (x) - q (x)$ $= p(x) - q(x)$
$= (x^{2} - 1) - {5 (x - 1)}$ $= (x^2-1) - {5(x-1)}$
$= x^{2} - 1 - {5 x - 5}$ $= x^2-1 - {5x-5}$
$= x^{2} - 1 - 5 x + 5$ $= x^2-1 - 5x+5$
$= x^{2} - 5 x + 4$ $= x^2- 5x+4$

Thus, $(p - q) (x) = x^{2} - 5 x + 4$ $(p-q)(x)=x^2- 5x+4$ .

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If $p (x) = x^{2} - 1$ $p(x) = x^2 -1$ and $q (x) = 5 (x - 1)$ $q(x) = 5(x-1)$ , what is $(p - q) (x)$ $(p-q)(x)$ ?

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Explanation:

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If p(x)=x2−1p(x) = x^2 -1 and q(x)=5(x−1)q(x) = 5(x-1), what is (p−q)(x)(p-q)(x)?

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If $p (x) = x^{2} - 1$ $p(x) = x^2 -1$ and $q (x) = 5 (x - 1)$ $q(x) = 5(x-1)$ , what is $(p - q) (x)$ $(p-q)(x)$ ?