How do you solve this system of equations: $- 3 x - 3 y = 0 and - 3 x - 10 y = 14$ $-3x - 3y = 0 and - 3x - 10y = 14$ ?

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How do you solve this system of equations: $- 3 x - 3 y = 0 and - 3 x - 10 y = 14$ $-3x - 3y = 0 and - 3x - 10y = 14$ ?

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Answer 1 · 2017-12-14T04:34:00

$x = 2$ $x=2$ and $y = - 2$ $y=-2$

Explanation:

As $- 3 x - 3 y = 0$ $-3x-3y=0$ , $- 3 x = 3 y$ $-3x=3y$

Putting this in $- 3 x - 10 y = 14$ $-3x-10y=14$ we get

$3 y - 10 y = 14$ $3y-10y=14$

or $- 7 y = 14$ $-7y=14$

or $y = \frac{14}{- 7} = - 2$ $y=14/(-7)=-2$

and $- 3 x = 3 \times (- 2)$ $-3x=3×(-2)$

or $- 3 x = - 6$ $-3x=-6$

or $x = \frac{- 6}{- 3} = 2$ $x=(-6)/(-3)=2$

Hence $x = 2$ $x=2$ and $y = - 2$ $y=-2$

Answer 2 · 2017-12-14T04:34:25

x = 2 and y = -2

Explanation:

Given:

$- 3 x - 3 y = 0 and - 3 x - 10 y = 14$ $-3x - 3y = 0 and -3x - 10y = 14$

Let $- 3 x = 3 y$ $-3x = 3y$
Now, we substitute for $- 3 x$ $-3x$ in $- 3 x - 10 y = 14$ $-3x - 10y = 14$ , that is;

$3 y - 10 y = 14$ $3y - 10y = 14$
$- 7 y = 14$ $-7y = 14$
$y = - 2$ $color(red)(y = -2)$

Next, substitute the value of y in any one of the above equations to get the respective x value;

$- 3 x - 10 (- 2) = 14$ $-3x - 10(-2) = 14$
$- 3 x + 20 = 14$ $-3x + 20 = 14$
$- 3 x = - 6$ $-3x = -6$
$x = 2$ $color(red)(x = 2)$

Therefore, $x = 2$ $x = 2$ and $y = - 2 .$ $y = -2.$

Answer 3 · 2017-12-14T06:03:20

$x = 2 and y = - 2$ $x=2 and y=-2$

Explanation:

Note that the terms in $x$ $x$ are the same in each equation.

Isolate the $x$ $x$ term, make it the subject in each equation.

$- 3 x = 3 y and - 3 x = 10 y + 14$ $-3x = 3y" "and" " -3x = 10y+14$

We know that $- 3 x = - 3 x$ $-3x =-3x$ , so equating the right sides gives:

$10 y + 14 = 3 y \leftarrow$ $10y +14 = 3y" "larr$ now solve for $y$ $y$

$10 y - 3 y = - 14$ $10y -3y = -14$

$7 y = - 14$ $7y = -14$

$y = - 2$ $y =-2$

Use the value of $y$ $y$ to find $x$ $x$

$- 3 x = 3 (- 2)$ $-3x = 3(-2)$

$- 3 x = - 6$ $-3x = -6$

$x = 2$ $x =2$

Check in the second equation.

$- 3 x = 10 y + 14$ $-3x = 10y+14$

$- 3 (2) and 10 (- 2) + 14$ $-3(2)" "and" "10(-2)+14$

$- 6 and - 20 + 14$ $-6" " and " "-20+14$

$- 6 = - 6$ $-6=-6$

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How do you solve this system of equations: $- 3 x - 3 y = 0 and - 3 x - 10 y = 14$ $-3x - 3y = 0 and - 3x - 10y = 14$ ?

3 Answers

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Science

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Humanities

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How do you solve this system of equations: −3x−3y=0and−3x−10y=14-3x - 3y = 0 and - 3x - 10y = 14?

3 Answers

Explanation:

Explanation:

Explanation:

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How do you solve this system of equations: $- 3 x - 3 y = 0 and - 3 x - 10 y = 14$ $-3x - 3y = 0 and - 3x - 10y = 14$ ?