How do you solve this system of equations: 3x3y=0and3x10y=14?

3 Answers
Dec 14, 2017

x=2 and y=2

Explanation:

As 3x3y=0, 3x=3y

Putting this in 3x10y=14 we get

3y10y=14

or 7y=14

or y=147=2

and 3x=3×(2)

or 3x=6

or x=63=2

Hence x=2 and y=2

Dec 14, 2017

x = 2 and y = -2

Explanation:

Given:

3x3y=0and3x10y=14

Let 3x=3y
Now, we substitute for 3x in 3x10y=14, that is;

3y10y=14
7y=14
y=2

Next, substitute the value of y in any one of the above equations to get the respective x value;

3x10(2)=14
3x+20=14
3x=6
x=2

Therefore, x=2 and y=2.

Dec 14, 2017

x=2andy=2

Explanation:

Note that the terms in x are the same in each equation.

Isolate the x term, make it the subject in each equation.

3x=3y and 3x=10y+14

We know that 3x=3x, so equating the right sides gives:

10y+14=3y now solve for y

10y3y=14

7y=14

y=2

Use the value of y to find x

3x=3(2)

3x=6

x=2

Check in the second equation.

3x=10y+14

3(2) and 10(2)+14

6 and 20+14

6=6