Question #25c38

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Answer 1 · 2017-12-19T14:26:56

$x=4$

Alright, this is just a simply matter of solving for $x$ .

First, subtract $x^3$

$0=x^3-64$

$0-x^3=x^3-64-x^3$

$-x^3=-64$

Next divide by $-1$ to get rid of both negatives

$(cancel-x^3)/(cancel-1)=(cancel-64)/(cancel-1)$

$x^3=64$

Finally, take the cube root

$x=64^((1/3))$

$x=4$

Hope this helped!
~Chandler Dowd