Question #588e9

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Answer 1 · 2017-12-20T04:50:55

$f(-6) = 780$

I believe the question is saying;

$f(x) = 23x^2 + 8x$

We are asked to solve for the value of the function when $x=-6$ . To do that, we need to plug in $-6$ for every instance of $x$ .

$f(-6) = 23(-6)^2 +8(-6)$

The correct order of operations is to handle the exponent, $(-6)^2$ , first.

$f(-6) = 23(36)+8(-6)$

Multiplication next.

$f(-6) = 828 - 48$

Then, subtraction to finish the calculation.

$f(-6) = 780$