Question

Question #588e9

Answer 1

`f(-6) = 780`

Explanation:

I believe the question is saying;

`f(x) = 23x^2 + 8x`

We are asked to solve for the value of the function when `x=-6`. To do that, we need to plug in `-6` for every instance of `x`.

`f(-6) = 23(-6)^2 +8(-6)`

The correct order of operations is to handle the exponent, `(-6)^2`, first.

`f(-6) = 23(36)+8(-6)`

Multiplication next.

`f(-6) = 828 - 48`

Then, subtraction to finish the calculation.

`f(-6) = 780`