Question #43d07

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Question #43d07

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Answer 1 · 2018-01-02T06:01:15

1

Explanation:

The equation of the line is given by $y = m x + c$ $y = mx+c$
where, slope is given by $m$ $m$ and $c$ $c$ is the y-intercept.

The given equation is: $y = x - 2$ $y = x-2$
Which can be written as: $y = 1 x - 2$ $y = 1x-2$

Therefore, slope is 1.

Answer 2 · 2018-01-02T06:25:47

$1$ $1$

Explanation:

The equations of line can be written in the form $y = m x + b$ $y=mx+b$ (where m is slope of line and b is constant)
here it can be clearly seen that $m = 1$ $m=1$ and $b = - 2$ $b=-2$
Cheers!

Answer 3 · 2018-01-02T09:32:09

Alternate, Calculus Answer...

Explanation:

For any of those studying calculus:

The slope is the derivative:

$\Rightarrow \frac{d}{d x} (x - 2) = 1$ $=> d/(dx) ( x-2) = color(red)(1$

As $\frac{d}{d x} (a x^{n}) = a \cdot \frac{d}{d x} (x^{n}) = a \cdot n x^{n - 1}$ $d/(dx) ( ax^n) = a * d/(dx) ( x^n) = a* nx^(n-1)$

Where the derivative $\frac{d y}{d x}$ $(dy)/(dx)$ is a function that tells you the gradient at a specific point

$only for those studying Differential Calculus...$ $color(blue)( "only for those studying Differential Calculus...")$

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Question #43d07

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