Question #75eb0

1 Answer
Jan 3, 2018

#96%#

Explanation:

Suppose the side of square is #x#
Then its area = #x^2#

When there is 40% increment in the length of the side, the side length would become =#1.4x#

(#40%# = #40/100# = #0.4# and when #0.4x# is added to initial length #x#, the increased or new length becomes #1.4x#)

New Area of square with increased length = #(1.4x)^2# = #1.96x^2#

Now, percentage change in area of resultant square =

#((1.96x^2-x^2)/x^2)*100# = #96%#