How do you simplify $3- 4x - 7x^{2} + 4x^3= 2- 8x - 7x^2- x^{3}$ ?

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Answer 1 · 2018-01-10T08:08:49

There isn’t a absolute answer for this question. However, the simplified form is:
$4x+5x^3=-1$

$-4x+8x-7x^2+7x^2+4x^3+x^3=2-3$

$4x+5x^3=-1$

Answer 2 · 2018-01-10T08:13:47

$1+4x+5x^3=0$

Given -

$3-4x-7x^2+4x^3=2-8x-7x^2-x^3$

Add $-2$ to both sides

$3-2-4x-7x^2+4x^3=2-2-8x-7x^2-x^3$
$1-4x-7x^2+4x^3=cancel2cancel(-2)-8x-7x^2-x^3$
$1-4x-7x^2+4x^3=-8x-7x^2-x^3$

Add $8x$ to both sides

$1-4x+8x-7x^2+4x^3=-8x+8x-7x^2-x^3$
$1+4x-7x^2+4x^3=cancel(-8x)cancel(+8x)-7x^2-x^3$
$1+4x-7x^2+4x^3=-7x^2-x^3$

Add $7x^2$ to both sides

$1+4xcancel(-7x^2)cancel(+7x^2)+4x^3=cancel(-7x^2)cancel(+7x^2)-x^3$
$1+4x+4x^3=-x^3$

Add $x^3$ to both sides

$1+4x+4x^3+x^3=-x^3+x^3$
$1+4x+5x^3=cancel(-x^3)cancel(+x^3)$
$1+4x+5x^3=0$

How do you simplify 3- 4x - 7x^{2} + 4x^3= 2- 8x - 7x^2- x^{3}3- 4x - 7x^{2} + 4x^3= 2- 8x - 7x^2- x^{3}?