Question

Question #e8125

Answer 1

Normal force= 24 N
Frictional force acting downwards of 9.6 N in magnitude
Acceleration of the system is 1.2 `m/s^2`

Explanation:

Normal force acting is given by N=F `sin 37` i.e the force applied horizontally on the block.
N= `40*(3/5)` or 24 N
As the system is being mobilised upward frictional force will be acting against the direction of effective motion.
Its value will be `u*N`
Or,`(0. 40*24)`N i.e 9.6 N
Now,let's consider that the system moves upward with acceleration a,so from equation of force we can write,
F `cos 37-(u*N+m*g)`=`m*a`
Or,`a=1.2 m/s^2`