How do you solve #-27< 4.5( 4- n )#?

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Answer 1 · 2018-01-11T17:46:45

#n<10#

#-27<4.5(4-n)#

You can write #4.5# as #9/2#, now we have:

#-27<9/2(4-n)# #<=>#

#-27<36/2-(9n)/2# #<=>#

#-27<18-(9n)/2# #<=>#

#-54<36-9n# #<=>#

#-54-36<-9n# #<=>#

#-90<-9n# #<=>#

#9n<90# #<=>#

#n<90/9# #<=>#

#n<10#