How do you solve #3( v + 94) - - 66= 96#?

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Answer 1 · 2018-01-11T18:01:10

#color(blue)(v=-40)#

1) Expand the bracket, using BIDMAS or BODMAS respectively,

#color(red)(3xxv=3v#

#color(red)(3xx94=282)#

2) Plug into equation getting rid of previous values and brackets, giving us:

#color(blue)(3v+282-(-66)=96#

3) Solve like an equation:

#color(blue)(3v+282=66+96 (+66)#

#color(blue)(3v+282=162#

#color(blue)(3v=-120 (-282) #

#color(blue)(v=-120/3=-40#

Answer 2 · 2018-01-11T18:04:33

#u=-40# , #u=84#

#3(u+94)-66=96# #<=>#

#3u+3*94-66=96 <=>#

#3u+282-66=96# #<=>#

#3u+216=96# #<=>#

#3u=96-216# #<=>#

#3u=-120# #<=>#

#u=-120/3# #<=>#

#u=-40#

If you meant

#3(u+94)-(-66)=96# #<=>#

#3u+282+66=96# #<=>#

#3u+348=96# #<=>#

#3u=96-348# #<=>#

#3u=-252# #<=>#

#u=-252/3# #<=>#

#u=84#