How do you multiply $2 \sqrt{5} \cdot - 3 \sqrt{4}$ $2\sqrt { 5} \cdot - 3\sqrt { 4}$ ?

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How do you multiply $2 \sqrt{5} \cdot - 3 \sqrt{4}$ $2\sqrt { 5} \cdot - 3\sqrt { 4}$ ?

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Answer 1 · 2018-01-12T00:36:08

$- 12 \sqrt{5}$ $-12sqrt5$

Explanation:

$2 \sqrt{5} \times$ $2sqrt5xx$ $- 3 \sqrt{4}$ $-3sqrt4$

Multiply the coefficients and the square roots together

which would be, $2 \times (- 3)$ $2xx(-3)$ $(\sqrt{5} \times \sqrt{4}$ $(sqrt5xxsqrt4$ )

or, $- 6 \times \sqrt{5} \times 2$ $-6xxsqrt5xx2$ (because $\sqrt{4}$ $sqrt4$ is $2$ $2$ )

or, $- 12 \sqrt{5}$ $-12sqrt5$

Answer 2 · 2018-01-12T00:37:21

The Answer is -12 $\sqrt{5}$ $sqrt(5$

Explanation:

Always remember to factor the $\sqrt{4}$ $sqrt(4$ . After that, multiply the numbers that are outside the square roots. so 2 $\cdot$ $*$ -6. just add the $\sqrt{5}$ $sqrt(5$

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How do you multiply $2 \sqrt{5} \cdot - 3 \sqrt{4}$ $2\sqrt { 5} \cdot - 3\sqrt { 4}$ ?

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Explanation:

Explanation:

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