How do you simplify $\frac{{(x + h)}^{2} + 4 (x + h) 7 x^{2} - 4 x + 7}{h}$ $\frac { ( x + h ) ^ { 2} + 4( x + h ) 7x ^ { 2} - 4x + 7} { h }$ ?

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Answer 1 · 2018-01-13T00:31:29

$x^{2} + 2 h x + h^{2} + 28 x^{3} + 28 h x^{2} - 4 x + 7$ $x^2+2hx+h^2+28x^3+28hx^2-4x+7$

$\frac{{(x + h)}^{2} + 4 (x + h) 7 x^{2} - 4 x + 7}{h}$ $((x+h)^2+4(x+h)7x^2-4x+7)/h$

= $\frac{(x + h) (x + h) + (4 x + 4 h) 7 x^{2} - 4 x + 7}{h}$ $((x+h)(x+h)+(4x+4h)7x^2-4x+7)/h$

= $x^{2} + h x + h x + h^{2} + 28 x^{3} + 28 h x^{2} - 4 x + 7$ $x^2+hx+hx+h^2+28x^3+28hx^2-4x+7$

= $x^{2} + 2 h x + h^{2} + 28 x^{3} + 28 h x^{2} - 4 x + 7$ $x^2+2hx+h^2+28x^3+28hx^2-4x+7$

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How do you simplify (x+h)2+4(x+h)7x2−4x+7h\frac { ( x + h ) ^ { 2} + 4( x + h ) 7x ^ { 2} - 4x + 7} { h }?