How do you solve 8n ^ { 2} + 56n = - 488n2+56n=−48?

1 Answer
Manikandan S.
Jan 14, 2018

8n^2+56n= -488n2+56n=−48
8n^2+56n+48=08n2+56n+48=0

Divide by 8 throughout \implies⇒

n^2+7n+6 = 0n2+7n+6=0

Now you factorize 6 and look for the combination that results in +6 and has a sum of +7.

We have the following pairs of roots(1,6),(-1,-6),(3,2),(-3,-2)(1,6),(−1,−6),(3,2),(−3,−2) that give +6. The first set gives the sum of +7. So the equation can be written as

n^2+n+6n+6 = 0n2+n+6n+6=0
n(n+1)+6(n+1) = 0n(n+1)+6(n+1)=0
(n+1)(n+6) = 0(n+1)(n+6)=0
n = -1,-6n=−1,−6

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