How do you solve $x^{2} + x = 25 + x$ $x^ { 2} + x = 25+ x$ ?

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How do you solve $x^{2} + x = 25 + x$ $x^ { 2} + x = 25+ x$ ?

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Answer 1 · 2018-01-15T22:31:14

$x = \pm 5$ $x = +-5$

Explanation:

$x^{2} + x = 25 + x$ $x^2 + x = 25 + x$
$x^{2} + x - x = 25 + x - x$ $x^2 + x - x = 25 + x - x$
$x^{2} = 25$ $x^2 = 25$
$x = \sqrt{25} = \pm 5$ $x = sqrt25 = +-5$

It's $\pm 5$ $+-5$ because both $5^{2}$ $5^2$ and ${(- 5)}^{2}$ $(-5)^2$ are equal to 25

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How do you solve $x^{2} + x = 25 + x$ $x^ { 2} + x = 25+ x$ ?

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