Question

Question #4e3c8

Answer 1

The total energy required is 1540.2 kJ, which incorporates both the energy required to heat the Tin to its melting point and the energy required to melt it.

Explanation:

This is a two part problem. First, we must find the energy necessary to heat the tin to its melting point. Second, we must find the energy necessary to melt the tin at its melting point. So, let's start with heating the tin from room temperature (23 C):

We can find the amount of energy needed to heat the Tin to a specific temperature using the equation `q = m*c*DeltaT` , where `m` is mass, in kg, `c` is specific heat, in kJ/kg*C, and
`DeltaT = T`final - `T`initial, in Kelvin.
Initial Temperature 23 C = 296 Kelvin
Final temperature 231 C = 504 Kelvin
Now we plug in and solve.
`q = m*c*DeltaT`
`q = 15*.21*(504-296)`
`q = 655.2 kJ`

This is only the first half of the problem, as now we have to deal with the energy necessary to melt the Tin.

It is given that the heat of fusion of Tin is 59 kJ/kg, meaning that it requires 59 kJ to melt One kilogram of Tin. We have 15 kilograms, so we must multiply this value by 15.

`59 (kJ)/(kg) * 15 kg = 885 kJ`

Now to find the total energy, we just add the amount of energy to heat up the Tin and to melt it.

Total Energy = 655.2 kJ + 885 kJ = 1540.2 kJ required to melt 15 kg of Tin at room temperature.