Question

Question #f6eef

Answer 1

`2 m^-1`

Explanation:

Wave number = `1/lambda` (where, `lambda` is the wavelength)

From the given equation,comparing it with `y=a sin (omegat-theta)` we get, `omega=100 pi`

so,frequency(`nu`) =`omega/(2pi)` = `50 Hz`

now,we know `c=nulambda` (where `c` is the velocity of the wave)

so, `1/lambda = 2 m^-1`

Answer 2

`k=3.14m^-1`

Explanation:

The speed of a wave is:
`v=flamda`
In terms of `omega` and wave number:
`v = (2pif)/(2pi1/lamda) = omega/k`
`rArr k = omega/v = (100pi/cancels)/(100m/cancels) = pi/m = 3.14m^-1`