What will happen to the surface area of a rectangular prism if all three of its dimensions are doubled? Tripled? Explain your answer?

1 Answer
Jan 18, 2018

#A_("Double")=4A#

#A_("Triple")=9A#

Explanation:

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The surface area of a prism is equal to the surface areas of the sides plus the surface areas of the base and the top. In a rectangular prism, all six surfaces are rectangles as shown below:

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Since the area of a rectangle is equal to length X width, (#l*w#, the surface area of the sides can be calculated by multiplying the perimeter of the base by the height:

Surface Area of sides#=2(l+w)h#

Surface area of the base#=lw#

Surface area of the top#=lw#

Total surface Area =#A=2(l+w)h+2lw=2(lh+wh+lw)#

If we double all three dimensions we get:

#A_("Double")=2[(2l)(2h)+(2w)(2h)+(2l)(2w)]#

#A_("Double")=2(4lh+4wh+4lw)#

#A_("Double")=4[2(lh+wh+lw)]#

#A_("Double")=4A#

Doubling the dimensions makes the surface area #4# times the original surface area.

#A_("Triple")=2[(3l)(3h)+(3w)(3h)+(3l)(3w)]#

#A_("Triple")=2(9lh+9wh+9lw)#

#A_("Triple")=9[2(lh+wh+lw)]#

#A_("Triple")=9A#

Tripling the dimensions makes the surface area #9# times the original surface area.