Question #07d97

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Answer 1 · 2018-01-21T08:27:26

$- 0.307$ $-0.307$

You now have $lim_(xrarr1)ln((x+1)/(x-1))$

Directly inputting for $x$ will not work, as you will be required to solve $2/0$ , an impossible feat.

Remember the laws of logarithms, that can be applied to natural logs: $ln(a/b)=lna-lnb$ .

So now:

$lim_(xrarr1)ln(x+1)-ln(x-1)$

Now you can input the values:

$ln(1+1)-ln(1-1)$

$ln2-ln0$
But wait! $ln 0$ is undefined! So $ln((x+1)/(x-1))$ is undefined at $x=1$ .

So the answer is infinity.