Question #08486

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Question #08486

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Answer 1 · 2018-01-25T11:17:45

$= 5.227 \cdot 10^{- 19} J$ $=5.227*10^-19J$

Explanation:

The energy of a photon is equal to $\frac{h c}{λ}$ $(hc)/lambda$ , where $h$ $h$ is Planck's constant, $c$ $c$ is the speed of light, and $λ$ $lambda$ is the wavelength in meters.

So here we have:
$h = 6.626 \cdot 10^{- 34} m^{2} k g s^{- 1}$ $h=6.626*10^-34 m ^2kgs^-1$
$c = 299792458 m s^{- 1}$ $c=299 792 458ms^-1$
$λ = 380 \cdot 10^{- 9} m$ $lambda=380*10^-9m$

So input:
$\frac{6.626 \cdot 10^{- 34} \cdot 299792458}{380 \cdot 10^{- 9}}$ $(6.626*10^-34*299 792 458)/(380*10^-9)$

$= 5.227 \cdot 10^{- 19} J$ $=5.227*10^-19J$

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Question #08486

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